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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    Equation of a line through the origin and perpendicular to, the line joining (a, 0) and (- a, 0), is              [MP PET 1984]

    A) \[y=0\]                                      

    B) \[x=0\]

    C) \[x=-\ a\]                                   

    D) \[y=-\ a\]

    Correct Answer: B

    Solution :

    The required equation passing through (0, 0) and its gradient is \[m=\frac{1}{0}\], is \[y=\frac{1}{0}x\Rightarrow x=0\].


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