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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of the line passing through the point (1, 2) and perpendicular to the line \[x+y+1=0\] is                 [MNR 1981]

    A)            \[y-x+1=0\]                             

    B)            \[y-x-1=0\]

    C)            \[y-x+2=0\]                             

    D)            \[y-x-2=0\]

    Correct Answer: B

    Solution :

               The line perpendicular to the line \[x+y+1=0\] is \[y-x+\lambda =0\]. Also, it passes through the point (1, 2); \[\therefore \] \[\lambda =-1\]. Hence, required line is\[y-x-1=0\].


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