A) \[\frac{x}{a}+\frac{y}{b}+\frac{a}{b}=0\]
B) \[\frac{x}{b}+\frac{y}{a}=\frac{b}{a}\]
C) \[\frac{x}{b}+\frac{y}{a}=0\]\[\]
D) \[\frac{x}{b}+\frac{y}{a}=\frac{a}{b}\]
Correct Answer: D
Solution :
The given line is \[bx-ay=ab\] Obviously it cuts \[x\]-axis at (a, 0). The equation of line perpendicular to (i) is \[ax+by=k\], but it passes through (a, 0) Þ \[k={{a}^{2}}\]. Hence required equation of line is \[ax+by={{a}^{2}}\] i.e., \[\frac{x}{b}+\frac{y}{a}=\frac{a}{b}\].
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