A) 22%
B) 20%
C) 33%
D) 44%
Correct Answer: B
Solution :
\[T=2\,\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{{{l}_{2}}}{{{l}_{1}}}}\]\[=\sqrt{\frac{144}{100}}=\frac{12}{10}\] Þ T2 = 1.2 T1 Hence % increase \[=\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}\times 100=20%\]
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