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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    The time period of a simple pendulum is 2 sec. If its length is increased 4 times, then its period becomes                                                                    [CBSE PMT 1999; DPMT 1999]

    A)            16 sec                                      

    B)            12 sec

    C)            8 sec                                        

    D)            4 sec

    Correct Answer: D

    Solution :

               \[T\propto \sqrt{l}\]Þ \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{l}_{1}}}{{{l}_{2}}}}\] Þ \[\frac{2}{{{T}_{2}}}=\sqrt{\frac{l}{4l}}\] Þ \[{{T}_{2}}=4sec\]


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