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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    The period of simple pendulum is measured as T in a stationary lift. If the lift moves upwards with an acceleration of 5 g, the period will be                                                      [MNR 1979]

    A)            The same                              

    B)            Increased by 3/5

    C)            Decreased by 2/3 times  

    D)            None of the above

    Correct Answer: D

    Solution :

               \[\frac{{{T}'}}{T}=\sqrt{\frac{g}{g'+a}}=\sqrt{\frac{g}{g+5g}}=\sqrt{\frac{1}{6}}\]Þ \[{T}'=\frac{T}{\sqrt{6}}\]


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