2. Questions Bank
  3. 7th Class
  4. Mathematics
  5. Simple Equations

7th Class Mathematics Simple Equations Question Bank Simple Equations

  • question_answer
    The present age of A is twice that of B. 30  years from now, age of A will be \[1{}^{1}/{}_{2}\]times that of B. Find the present ages (in years) of A and B respectively.

    A)  \[60,\,\,30\]                       

    B)         \[30,\,\,60\]

    C)  \[40,\,\,50\]                     

    D)         \[50,\,\,40\]

    Correct Answer: A

    Solution :

       Let the present ages of A and B be \[2x\] years and x years. After 30 years, their ages will be \[A=(2x+30)\] years \[B=(x+30)\] years So,  \[2x+30=1\frac{1}{2}(x+30)\] \[\Rightarrow \] \[x=30\] \[\therefore \]Present age of \[B=30\]years \[\Rightarrow \] Present age of \[~A=2\times 30=60\] years


You need to login to perform this action.
You will be redirected in 3 sec spinner