A) Energy
B) Force
C) Energy per unit volume
D) Force per unit volume
Correct Answer: C
Solution :
Pressure \[=\frac{\text{Force}}{\text{Area}}\]\[=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Energy per unit volume \[=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{L}^{3}}]}=[M{{L}^{-1}}{{T}^{-2}}]\]
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