question_answer

Let \[U\] be the universal set and\[A\cup B\cup C=U\]. Then \[\{(A-B)\cup (B-C)\cup (C-A){\}}'\] is equal to

A) \[A\cup B\cup C\]

B) \[A\cup (B\cap C)\]

C) \[A\cap B\cap C\]

D) \[A\cap (B\cup C)\]

Correct Answer: C

Solution :

From Venn-Euler's Diagram, Clearly, \[\{(A-B)\cup (B-C)\cup (C-A){\}}'=A\cap B\cap C\].