A) \[\{x:x\] is a real number and \[{{x}^{2}}-1=0\}\]
B) {x : x is a real number and \[{{x}^{2}}+1=0\}\]
C) {x : x is a real number and \[{{x}^{2}}-9=0\}\]
D) {x : x is a real number and \[{{x}^{2}}=x+2\}\]
Correct Answer: D
Solution :
Since \[{{x}^{2}}+1=0,\] gives \[{{x}^{2}}=-1\] \[\Rightarrow \] \[x=\pm i\] \[\therefore \] x is not real but x is real (given) \[\therefore \] No value of x is possible.
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