6th Class Mathematics Related to Competitive Exam Question Bank Series

  • question_answer
    2, 3, 10, 15, 26,?

    A) 37       

    B)                                  36

    C) 35                   

    D)          48

    Correct Answer: C

    Solution :

        Each term is of the type \[{{n}^{2}}+1,\,\,{{n}^{2}}-1,\] alternately, e.g. \[2={{1}^{2}}+1\] \[3={{2}^{2}}-1\] \[10={{3}^{2}}+1\]


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