Answer:
The reverse biasing results in very high resistance across the p-n junction. If the value of the resistance R is increased, the current in the forward biased input circuit decreases. The emitter current \[{{I}_{E}}\] decreases and hence the collector current \[({{I}_{C}}={{I}_{E}}-{{I}_{B}})\] also decreases. The glowness of the bulb decreases. Due to decrease in \[{{I}_{C}}\], the potential drop across the bulb B decreases and hence the voltmeter shows a lower voltage.
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