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JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    The energy of an electron in first Bohr orbit of Pi- atom is \[-13.6\text{ }eV\]. The energy value of electron in the excited state of \[L{{i}^{2+}}\] is:

    A) \[-27.2\text{ }eV\]      

    B) \[30.6\text{ }eV\]

    C) \[-30.6eV\]        

    D) \[27.2\text{ }eV\]

    Correct Answer: C

    Solution :

    [c]  For \[L{{i}^{2+}}\]ion \[E=-13.6\times \frac{{{Z}^{2}}}{{{n}^{2}}}=-13.6\times \frac{{{(3)}^{2}}}{{{(2)}^{2}}}\] \[=\frac{-13.6\times 9}{4}=-30.6eV\]


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