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JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    The dissociation energy of \[{{H}_{2}}\] is \[430.53\text{ }kJmo{{l}^{-1}}\]. If hydrogen is dissociated by illumination with radiation of wavelength 253.7 nm the fraction of the radiant energy which will be converted into kinetic energy is given by

    A) 100%   

    B) 8.82%

    C) 2.22%  

    D) 1.22%

    Correct Answer: B

    Solution :

    [b] Energy of 1 mole of photons, \[E={{N}_{0}}\times {{h}_{v}}\] \[=\frac{{{N}_{0}}\times h\times c}{\lambda }\] \[=\frac{6.023\times {{10}^{23}}\times 6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{253.7\times {{10}^{-9}}}\] Energy converted into \[KE=\left( 472.2-430.53 \right)kJ%\]% of energy converted into \[KE=\frac{\left( 472.2-430.53 \right)}{472.2}\times 100=8.82%\]%


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