A) \[{{M}_{2}}=2{{M}_{1}}\]
B) \[{{M}_{1}}<10({{m}_{p}}+{{m}_{n}})\]
C) \[{{M}_{2}}>2{{M}_{1}}\]
D) \[{{M}_{1}}={{M}_{2}}\]
Correct Answer: A
Solution :
[a] \[_{20}^{40}Ne\]contains 10 protons and 10 neutrons \[\therefore {{M}_{1}}=10{{m}_{p}}+10{{m}_{n}}\] \[_{20}^{40}Ca\]contains 20 protons and 20 neutrons \[\therefore {{M}_{2}}=20{{m}_{p}}+20{{m}_{n}}\] \[\therefore {{M}_{2}}=2{{M}_{1}}\]
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