A) 3
B) 4
C) 16
D) 25
Correct Answer: C
Solution :
[c] \[{{r}_{1}}=0.529\overset{{}^\circ }{\mathop{A}}\,;{{R}_{4(x)}}={{R}_{1}}\times \frac{{{n}^{2}}}{Z};\] \[{{R}_{4(x)}}\Rightarrow \frac{0.529\times {{(4)}^{2}}}{Z};Z=16\]
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