A) \[-54.47\times {{10}^{-12}}erg\text{ }ato{{m}^{-1}}\]
B) \[-5.447\times {{10}^{-12}}erg\text{ }ato{{m}^{-1}}\]
C) \[-0.5447\times {{10}^{-12}}erg\text{ }ato{{m}^{-1}}\]
D) \[-0.05447\times {{10}^{-12}}erg\text{ }ato{{m}^{-1}}\]
Correct Answer: B
Solution :
[b] If we assume the atom to be hydrogen like, energy of nth energy level \[{{E}_{n}}=-\frac{{{E}_{1}}}{{{E}_{2}}}\] where\[{{E}_{1}}\] is energy of first energy level \[{{E}_{2}}=-\frac{{{E}_{1}}}{{{2}^{2}}}=-\frac{{{E}_{1}}}{4}=\frac{-21.79\times {{10}^{-12}}}{4}\] \[=-5.447\times {{10}^{-12}}\]erg per atom.
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