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JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    The de Broglie wavelength of a car of mass 1000 kg and velocity 36 km/hr is:

    A) \[6.626\times {{10}^{-34}}m\]   

    B) \[6.626\times {{10}^{-38}}m\]

    C) \[6.626\times {{10}^{-31}}m\]  

    D) \[6.626\times {{10}^{-30}}m\]

    Correct Answer: B

    Solution :

    [b] \[\lambda =\frac{h}{mv}\] \[h=6.6\times {{10}^{-34}}J-s\] \[m=1000kg\] \[v=36km/hr=\frac{36\times {{10}^{3}}}{60\times 60}m/sec=10m/sec\] \[\therefore \lambda =\frac{6.6\times {{10}^{-34}}}{{{10}^{3}}\times 10}=6.6\times {{10}^{-38}}m\]


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