question_answer

What will be the difference between electromagnetic radiation shown in A and B respectively?

(i)  Velocity

(ii) Wavelength

(iii) Frequency

(iv) Energy

 

A) (ii) only      

B) (ii) and (iv)

C) (ii), (iii) and (iv)

D) (iv) only

Correct Answer: C

Solution :

[c] e/m waves shown in figure A has higher wavelength in comparison to e/m waves shown in figure B. Thus these waves also differ in frequency and energy, \[v=\frac{v}{\lambda }\] \[\Rightarrow {{E}_{1}}=\frac{hc}{{{\lambda }_{1}}}\] \[\Rightarrow {{E}_{2}}=\frac{hc}{{{\lambda }_{2}}}{{\lambda }_{1}}>{{\lambda }_{2}}\Rightarrow {{E}_{1}}<{{E}_{2}}\]