JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within \[5.0\times {{10}^{-26}}kg\,m{{s}^{-1}}\]. The minimum uncertainty in the measurement of the momentum of the helium atom is

    A) \[50kgm{{s}^{-1}}\]      

    B) \[80kgm{{s}^{-1}}\]

    C) \[8.0\times {{10}^{-26}}kg\text{ }m{{s}^{-1}}\]         

    D) \[5.0\times {{10}^{-26}}kg\text{ }m{{s}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] According to Heisenberg uncertainty principle, \[\Delta x\times \Delta p=\frac{h}{4\pi }\] (which is constant). As \[\Delta x\]for electron and helium atom is same, thus momentum of electron and helium will also be same, therefore the momentum of helium atom is equal to \[5\times {{10}^{-26}}kgm{{s}^{-~1}}.\]


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