A) 9 sigma bonds, 1 pi bond and 2 lone pairs
B) 8 sigma bonds, 2 pi bonds and 2 lone pairs
C) 10 sigma bonds, 1 pi bond and 1 lone pair
D) 9 sigma bonds, 2 pi bonds and 1 lone pair
Correct Answer: A
Solution :
\[\,C{{H}_{3}}-\overset{\overset{_{\bullet }^{\bullet }\overset{\bullet \ \ \bullet }{\mathop{O}}\,-H\,\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{C=\,C{{H}_{2}}\,}}\,\] has 9s, 1p and 2 lone pairs.
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