JEE Main & Advanced Mathematics Sets Question Bank Relations

  • question_answer
    If \[R=\{(x,\,y)|x,\,y\in Z,\,{{x}^{2}}+{{y}^{2}}\le 4\}\] is a relation in Z, then domain of R is

    A) {0, 1, 2}

    B) {0, - 1, - 2}

    C) {- 2, - 1, 0, 1, 2}

    D) None of these

    Correct Answer: C

    Solution :

    \[\because \,R=\{(x,\,y)|x,\,y\in Z,\,{{x}^{2}}+{{y}^{2}}\le 4\}\] \[\therefore \] \[R=\{(-2,\,0),(-1,\,0),(-1,\,1),(0,\,-1)(0,\,1),(0,\,2),(0,-2)\]\[(1,\,0),(1,\,1),(2,\,0)\}\] Hence, Domain of\[R=\{-2,\,-1,\,0,\,1,\,2\,\}\].


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