A) \[\frac{1}{2}\]
B) \[\sqrt{3}\]
C) \[\frac{\sqrt{3}}{2}\]
D) \[\frac{3}{2}\]
Correct Answer: C
Solution :
We have, \[a=1,\,b=2,\,\angle C=60{}^\circ \] Area of triangle = \[\frac{1}{2}ab\sin C\] = \[\frac{1}{2}(1)\,(2)\,\sin 60{}^\circ =\frac{\sqrt{3}}{2}\].
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