JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Relation between sides and angles, Solutions of triangles

  • question_answer
    If \[{{p}_{1}},{{p}_{2}},{{p}_{3}}\] are altitudes of a triangle \[ABC\]from the vertices \[A,B,C\] and \[\Delta \] the area of the triangle, then \[p_{1}^{-2}+p_{2}^{-2}+p_{3}^{-2}\] is equal to

    A) \[\frac{a+b+c}{\Delta }\]

    B) \[\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{4{{\Delta }^{2}}}\]

    C) \[\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{{{\Delta }^{2}}}\]

    D) None of these

    Correct Answer: B

    Solution :

    We have \[\frac{1}{2}a{{p}_{1}}=\Delta ,\frac{1}{2}b{{p}_{2}}=\Delta ,\frac{1}{2}c{{p}_{3}}=\Delta \] Þ \[{{p}_{1}}=\frac{2\Delta }{a},{{p}_{2}}=\frac{2\Delta }{b},{{p}_{3}}=\frac{2\Delta }{c}\] \ \[\frac{1}{p_{1}^{2}}+\frac{1}{p_{2}^{2}}+\frac{1}{p_{3}^{2}}=\frac{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}{4{{\Delta }^{2}}}\].


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