A) \[{{30}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{90}^{o}}\]
D) None of these
Correct Answer: D
Solution :
\[\frac{a}{\sin A}=\frac{b}{\sin B}\] Þ \[\sin B=\frac{(b\sin A)}{a}=\frac{(4\sqrt{3}\sin {{60}^{o}})}{5}=\frac{6}{5}>1\], which is inadmissible.
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