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JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Relation between sides and angles, Solutions of triangles

  • question_answer
    The number of triangles ABC that can be formed with \[a=3,b=8\] and \[\sin A=\frac{5}{13}\]is     [Roorkee Qualifying 1998]

    A) 0

    B) 1

    C) 2

    D) 3

    Correct Answer: A

    Solution :

    Applying sine rule, \[\frac{\sin B}{b}=\frac{\sin A}{a}\]or \[\frac{\sin B}{8}=\frac{5/13}{3}\] or \[\sin B=\frac{40}{39}>1\], which is not possible. Hence no triangle can be formed by the given conditions.


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