A) 10, 10
B) \[10,\,10\sqrt{3}\]
C) \[5,\,\,5\sqrt{3}\]
D) \[8,\,\,8\sqrt{3}\]
Correct Answer: B
Solution :
\[\angle C={{90}^{o}},\angle A={{30}^{o}},c=20,\] then \[a=\frac{c\sin A}{\sin C}=10\] and \[b=\frac{c\sin B}{\sin C}=10\sqrt{3}\]. Trick: Since the angles are\[{{30}^{o}},{{60}^{o}},{{90}^{o}}\], therefore sides must be\[1:\sqrt{3}:2\]. Hence\[a=10,b=10\sqrt{3}\].
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