A) \[\frac{1}{p}\]
B) \[\frac{1}{q}\]
C) \[\frac{1}{2p}\]
D) \[\frac{p}{q}\]
Correct Answer: D
Solution :
Roots of given equation \[{{x}^{2}}-px+q=0\] is \[a\] and \[b\] i.e., \[a+b=p\] ??(i) and \[ab=q\] ??(ii) Then\[\frac{1}{a}+\frac{1}{b}=\frac{a+b}{ab}=\frac{p}{q}\].
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