A) \[\pi /4\]
B) 1
C) 0
D) \[\pi /2\]
Correct Answer: A
Solution :
\[\alpha +\beta =\frac{5}{6},\,\,\alpha \beta =\frac{1}{6}\] \[{{\tan }^{-1}}\alpha +{{\tan }^{-1}}\beta ={{\tan }^{-1}}\left( \frac{\alpha +\beta }{1-\alpha \beta } \right)\] =\[{{\tan }^{-1}}\left( \frac{5/6}{1-(1/6)} \right)={{\tan }^{-1}}(1)=\frac{\pi }{4}\].
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