A) \[n=0\]
B) \[m=n\]
C) \[m+n=1\]
D) \[{{m}^{2}}+{{n}^{2}}=1\]
Correct Answer: A
Solution :
Given, \[\frac{x-m}{mx+1}=\frac{x+n}{nx-1}\] Þ \[{{x}^{2}}(m-n)+2mnx+(m+n)=0\] Roots are \[\alpha ,\frac{1}{\alpha }\] respectively, then \[\alpha .\frac{1}{\alpha }=\frac{m+n}{m-n}\] Þ \[m-n=m+n\] Þ \[n=0\].
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