A) \[{{p}^{2}}+\frac{c}{a}\]
B) \[{{p}^{2}}+\frac{a}{c}\]
C) \[{{p}^{2}}+\frac{a}{b}\]
D) \[{{p}^{2}}+\frac{b}{a}\]
Correct Answer: A
Solution :
From the given equations, we find that q and r are roots of the equation \[a{{(p+x)}^{2}}+2bpx+c=0\] or\[a{{x}^{2}}+2x(a+b)p+a{{p}^{2}}+c=0\]. Now product of the roots is \[qr=\frac{a{{p}^{2}}+c}{a}={{p}^{2}}+\frac{c}{a}\].
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