A) \[{{x}^{2}}-14x+74=0\]
B) \[{{x}^{2}}+14x+74=0\]
C) \[{{x}^{2}}-14x-74=0\]
D) \[{{x}^{2}}+14x-74=0\]
Correct Answer: A
Solution :
Let\[\alpha =7+5i\], then its conjugate\[\beta =7-5i\], so required equation is given by \[{{x}^{2}}-(\alpha +\beta )x+\alpha \beta =0\] Þ \[{{x}^{2}}-(14)x+(49+25)=0\]Þ \[{{x}^{2}}-14x+74=0\]
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