A) 0
B) 1
C) 2
D) None of these
Correct Answer: A
Solution :
Given equation \[\frac{\alpha }{x-\alpha }+\frac{\beta }{x-\beta }=1\] can be written as Þ \[{{x}^{2}}-2(\alpha +\beta )x+3\alpha \beta =0\] Let roots are \[{\alpha }'\] and \[-{\alpha }'\] \[{\alpha }'+(-{\alpha }')=2(\alpha +\beta )\Rightarrow 0=2(\alpha +\beta )\,\,\Rightarrow \alpha +\beta =0\].
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