A) \[a=b\ne c\]
B) \[a\ne b=c\]
C) \[a\ne b\ne c\]
D) \[a=b=c\]
Correct Answer: D
Solution :
As given \[b=\frac{a+c}{2}\] ?..(i) and \[{{b}^{2}}=ac\] ?..(ii) \[\Rightarrow {{(a+c)}^{2}}=4ac\Rightarrow {{(a-c)}^{2}}=0\Rightarrow a=c\] Putting \[a=c\] in (i), we get \[b=c\]; \[\therefore \]\[a=b=c\].
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