JEE Main & Advanced Mathematics Sequence & Series Question Bank Relation between AP., GP. and HP.

  • question_answer
    If the arithmetic mean of two numbers be \[A\] and geometric mean be\[G\], then the numbers will be

    A) \[A\pm ({{A}^{2}}-{{G}^{2}})\]

    B) \[\sqrt{A}\pm \sqrt{{{A}^{2}}-{{G}^{2}}}\]

    C) \[A\pm \sqrt{(A+G)(A-G)}\]

    D) \[\frac{A\pm \sqrt{(A+G)(A-G)}}{2}\]

    Correct Answer: C

    Solution :

    A.M. \[=\frac{a+b}{2}=A\] and G.M. \[=\sqrt{ab}=G\] On solving \[a\] and \[b\]are given by the values \[A\pm \sqrt{(A+G)(A-G)}\]. Trick: Let the numbers be 1, 9. Then \[A=5\] and \[G=3\]. Now put these values in options. Here (c) \[\Rightarrow 5\pm \sqrt{8\times 2}\ i.e.\] 9 and 1.


You need to login to perform this action.
You will be redirected in 3 sec spinner