A) 0.33
B) 0.75
C) 0.85
D) 3.00
Correct Answer: B
Solution :
\[\frac{Vol.\ \text{of }C{{\text{O}}_{2}}}{\text{Vol}\text{. of }{{O}_{2}}}\]\[=\frac{{{V}_{2}}\ cc}{{{V}_{1}}\ cc+{{V}_{2}}\ cc}\] \[\Rightarrow R.Q.\ =\ \frac{30\ cc}{10\ cc+30\ cc}=0.75\]
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