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Teaching Environmental Studies Travel and Communication Question Bank Questions - Travel

  • question_answer
    A person boarded an express train on 30th August, 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13:30 h and reached Trivandrum 7:30 h on 1st September, 2015. If the distance between Ahmedabad and Trivandrum is 2268 km, the average speed of the train between the two stations was (CTET Sept 2015)

    A) 42m/s

    B) 15m/s

    C) 9m/s

    D) 54m/s

    Correct Answer: B

    Solution :

    [b] Total time taken is 42 hours. Total distance is 2268 km. So, \[Speed=\frac{\text{Distance}}{\text{Time}}\] If it is km/ hour then we have to multiply this with \[\frac{5}{18}\] to convert in min/sec.             \[=\frac{2268}{42}\times \frac{5}{18}=15\,\min /\sec \]


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