A) Equilateral
B) Right-angled
C) Isosceles
D) None of these
Correct Answer: A
Solution :
Given, vertices of triangle are \[A(1,\,1),\,B(-1,\,-1)\] and \[C(-\sqrt{3},\,\sqrt{3})\] Now, \[AB=\sqrt{{{(-1-1)}^{2}}+{{(-1-1)}^{2}}}=\sqrt{4+4}=\sqrt{8}\] \[BC=\sqrt{{{(-\sqrt{3}+1)}^{2}}+{{(\sqrt{3}+1)}^{2}}}=\sqrt{8}\] \[CA=\sqrt{{{(1+\sqrt{3})}^{2}}+{{(1-\sqrt{3})}^{2}}}=\sqrt{8}\] i.e., \[AB=BC=CA\]. So, it is an equilateral triangle.
You need to login to perform this action.
You will be redirected in
3 sec
