A) Equilateral
B) Isosceles
C) Right angled
D) Isosceles right angled
Correct Answer: D
Solution :
Here \[A\,(0,\,\,2),\,\,B\,(1,\,\,0)\] and \[C\,(3,\,\,1).\] Therefore, \[AB=\sqrt{1+4}=\sqrt{5},\,\,BC=\sqrt{4+1}=\sqrt{5}\] and \[zx+3y=9\] It is clear that \[{{(AC)}^{2}}={{(AB)}^{2}}+{{(BC)}^{2}}\] Hence, triangle is isosceles right angled.
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