A) An isosceles triangle
B) An equilateral triangle
C) A right angled triangle
D) None of these
Correct Answer: C
Solution :
\[a=\sqrt{{{(8+2)}^{2}}+{{(-2-2)}^{2}}}=\sqrt{116}\] \[b=\sqrt{{{(-\,4-\,8)}^{2}}+{{(-\,3+2)}^{2}}}=\sqrt{145}\] \[c=\sqrt{{{(-\,4+2)}^{2}}+{{(-\,3-2)}^{2}}}=\sqrt{29}\]\[\Rightarrow \,\,{{a}^{2}}+{{c}^{2}}={{b}^{2}}\] Hence it is right angled triangle.
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