A) \[\frac{1}{2}\]
B) \[\frac{3}{4}\]
C) \[\frac{3}{8}\]
D) \[\frac{5}{16}\]
E) None of these
Correct Answer: B
Solution :
Explanation Option (b) is correct. In a simultaneous throw of two dice, we have n (S) = \[(6\times 6)=36\] Let E = event of getting two numbers whose product is even. Then, E = {(1,2), (1,4,) (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,2), (3,4), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,2), (5,4), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}. \[\therefore \,\,\,\,\,\,n(E)=27\] \[\therefore \,\,\,\,\,\,P(E)=\frac{n(E)}{n(S)}=\frac{27}{36}=\frac{3}{4}.\]
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