question_answer

The electronic configuration (outermost) of \[M{{n}^{+2}}\] ion (atomic number of \[Mn=25\]) in its ground state is [MP PET 1993]

A)                 \[3{{d}^{5}},4{{s}^{0}}\]               

B)                 \[3{{d}^{4}},4{{s}^{1}}\]

C)                 \[3{{d}^{3}},4{{s}^{2}}\]               

D)                 \[3{{d}^{2}},4{{s}^{2}}4{{p}^{2}}\]

Correct Answer: A

Solution :

                \[_{25}Mn=[Ar]\,3{{d}^{5}}4{{s}^{2}}\]\[M{{n}^{2+}}=[Ar]\,\,3{{d}^{5}}\,4{{s}^{0}}\]