JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer The electronic configuration (outermost) of \[M{{n}^{+2}}\] ion (atomic number of \[Mn=25\]) in its ground state is [MP PET 1993]

    A)                 \[3{{d}^{5}},4{{s}^{0}}\]               

    B)                 \[3{{d}^{4}},4{{s}^{1}}\]

    C)                 \[3{{d}^{3}},4{{s}^{2}}\]               

    D)                 \[3{{d}^{2}},4{{s}^{2}}4{{p}^{2}}\]

    Correct Answer: A

    Solution :

                    \[_{25}Mn=[Ar]\,3{{d}^{5}}4{{s}^{2}}\]\[M{{n}^{2+}}=[Ar]\,\,3{{d}^{5}}\,4{{s}^{0}}\]

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