A) \[5,\,0,\,0,\,+\frac{1}{2}\]
B) \[5,\,1,\,0,\,+\frac{1}{2}\]
C) \[5,\,1,\,1,\,+\frac{1}{2}\]
D) \[6,\,0,\,0,\,+\,\frac{1}{2}\]
Correct Answer: A
Solution :
Electronic configuration of \[R{{b}_{(37)}}\] is \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}4{{s}^{2}}4{{p}^{6}}5{{s}^{1}}\] So for the valence shell electron \[(5{{s}^{1}})\] \[n=5,\,l=0,\,m=0,\,s=+\frac{1}{2}\]
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