A) \[2n\]
B) \[2{{n}^{2}}\]
C) \[n\]
D) \[{{n}^{2}}\]
Correct Answer: D
Solution :
No. of electrons\[=2{{n}^{2}}\]hence no. of orbital \[=\frac{2{{n}^{2}}}{2}={{n}^{2}}\].
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