JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer The orbital angular momentum of an electron in \[2s\]-orbital is                                [MP PET 2004]

    A)                 \[\frac{1}{2}\frac{h}{2\pi }\]       

    B)                 \[\frac{h}{2\pi }\]

    C)                 \[\sqrt{2}\frac{h}{2\pi }\]            

    D)                 Zero

    Correct Answer: D

    Solution :

               Since s-orbital have \[l=0\]                                 Angular momentum = \[\sqrt{l\,(l+1)}\times \frac{h}{2\pi }\] = \[0\times \frac{h}{2\pi }=0\] .


You need to login to perform this action.
You will be redirected in 3 sec spinner