A) \[p\]-electrons in \[Ne\] (At. No.= 10)
B) \[s\]-electrons in \[Mg\] (At. No.= 12)
C) \[d\]-electrons in \[Fe\]
D) \[p\]-electrons in \[C{{l}^{-}}\] (At. No. of \[Cl\] = 17)
Correct Answer: D
Solution :
\[_{26}Fe=[Ar]\,3{{d}^{6}},\,4{{s}^{2}}\] \[F{{e}^{2+}}=[Ar]\,3{{d}^{6}},\,4{{s}^{0}}\] Number of d-electrons = 6 \[_{17}Cl=[Ne]\,3{{s}^{2}},\,3{{p}^{5}}\] \[C{{l}^{-}}=[Ne]\,3{{s}^{2}},\,3{{p}^{6}}\] Number of p-electrons = 6.
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