A) \[1{{s}^{2}}2{{s}^{2}}\]
B) \[1{{s}^{2}}2{{s}^{1}}\]
C) \[1{{s}^{2}}2{{s}^{2}}2p_{x}^{1}2p_{y}^{1}2p_{x}^{1}\]
D) \[1{{s}^{2}}2{{s}^{2}}2p_{x}^{2}\]
E) \[1{{s}^{2}}2{{s}^{2}}2p_{x}^{2}2p_{y}^{1}2p_{z}^{1}\]
Correct Answer: D
Solution :
According to Hund's rule electron first fill in unpaired form in vacant orbital then fill in paired form to stabilized the molecule by which \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{2}\] is not possible. According to Hund's rule. Because \[2{{p}_{x}},{{p}_{y}},{{p}_{z}}\] have the same energy level so electron first fill in unpaired form not in paired form so it should be \[1{{s}^{2}},\,2{{s}^{2}},\,2p_{x}^{1},2p_{y}^{1}\].
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