A) \[{{260}^{{}^\circ }}\]
B) \[{{150}^{{}^\circ }}\]
C) \[{{140}^{{}^\circ }}\]
D) \[{{288}^{{}^\circ }}\]
Correct Answer: D
Solution :
(d): By law of transversal, \[\angle A+\angle B={{180}^{{}^\circ }}\] \[\angle A=4\angle B\] \[\Rightarrow 5\angle B={{180}^{{}^\circ }}=\angle B={{36}^{{}^\circ }}\] \[\angle \,A=\angle C\] \[\therefore \angle A+\angle C=2\angle A\] \[\Rightarrow 2\times 4\times \angle B=8\angle B\] \[\Rightarrow 8\times {{36}^{{}^\circ }}={{288}^{{}^\circ }}\]You need to login to perform this action.
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