A) \[\angle A+\angle B=\angle CED\]
B) \[\angle A+\angle B\text{=}2\angle CED\]
C) \[\angle A+\angle B=3\angle CED\]
D) None of these
Correct Answer: B
Solution :
(b):\[\angle 1=\frac{1}{2}\angle C,\angle 2=\frac{1}{2}\angle D\] \[\angle 1+\angle 2+\angle CED={{180}^{{}^\circ }}\] \[\therefore \] \[\angle CED={{180}^{{}^\circ }}-\left( \angle 1+\angle 2 \right)\] Also \[\angle A+\angle B+\angle C+\angle D={{360}^{{}^\circ }}\] \[\angle A+\angle B+2\left( \angle 1+\angle 2 \right)={{360}^{{}^\circ }}\] \[\angle A+\angle B={{360}^{{}^\circ }}-2\left( \angle 1+\angle 2 \right)\] \[\angle A+\angle B=2\angle CED\]
You need to login to perform this action.
You will be redirected in
3 sec
